The Ellipse

Part 13, Chapter 13: Conic Sections in the Coordinate Plane

Learning objectives

  • Write the standard equation of an ellipse
  • Identify the major and minor axes
  • Find the foci and compute the eccentricity
  • Sketch an ellipse from its equation

Take a piece of string, pin its two ends to a table, and trace a curve while keeping the string taut. What you draw is an ellipse. The two pins are the foci; the curve is the locus of points where the sum of distances to the foci stays constant (equal to the string length). This pinned-string construction is more than a party trick, it is the geometric definition that explains Kepler's discovery that planets orbit the Sun in ellipses, the Sun sitting at one focus.

The standard equation

An ellipse centred at the origin with semi-axes aa along xx and bb along yy (with a,b>0a, b > 0) satisfies dfracx2a2+dfracy2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1. If a>ba > b, the ellipse is wider than tall and the major axis runs along the xx-axis with length 2a2a; the minor axis runs along yy with length 2b2b. The vertices and co-vertices are (pma,0)(\pm a, 0) and (0,pmb)(0, \pm b). If b>ab > a, swap roles.

Foci and eccentricity

The foci sit on the major axis at distance cc from the centre, where c=sqrta2b2c = \sqrt{a^2 - b^2} (foci at (pmc,0)(\pm c, 0)). The string length, the sum of distances from any point on the ellipse to the two foci, equals 2a2a. The eccentricity is e=c/ae = c/a with 0leqe<10 \leq e < 1. When e=0e = 0 the foci coincide at the centre and the ellipse is a circle. As eto1e \to 1 the ellipse stretches. Earth's orbit has eapprox0.017e \approx 0.017; Halley's comet has eapprox0.97e \approx 0.97.

Where this shows up
  • Astronomy: Planetary orbits are ellipses with the Sun at one focus (Kepler's first law); the eccentricity tells you how "oval" the orbit is, Earth's is 0.017, Mercury's 0.206, Halley's comet 0.967.
  • Architectural Acoustics: An elliptical chamber, like Statuary Hall in the US Capitol or the Mormon Tabernacle in Salt Lake City, reflects sound from one focus precisely to the other; standing at one focus, you hear a whisper from the other across the room.
  • Medicine: Lithotripsy uses an ellipsoidal water bath to focus shock waves: kidney stones at one focus are pulverised by sound waves originating at the other focus.

(Select "ellipse" mode. Slide aa and bb; watch the foci move as eccentricity changes.)

Shifted ellipses

An ellipse centred at (h,k)(h, k) satisfies (xh)2/a2+(yk)2/b2=1(x - h)^2/a^2 + (y - k)^2/b^2 = 1. The foci shift to (hpmc,k)(h \pm c, k). To find the centre of an ellipse given in expanded form, complete the square in both xx and yy.

Try it

  • Find the foci and eccentricity of x2/25+y2/9=1x^2/25 + y^2/9 = 1.
  • An ellipse has foci at (pm3,0)(\pm 3, 0) and vertices at (pm5,0)(\pm 5, 0). Find its equation.
  • For an ellipse with a=6,c=4a = 6, c = 4, what is bb?

Pause: if a=ba = b, then c=0c = 0, foci merge at the centre, and the ellipse is a circle.

A trap to watch for

The sign in c2=a2b2c^2 = a^2 - b^2 uses subtraction, but for the hyperbola the analogous formula uses addition: c2=a2+b2c^2 = a^2 + b^2. Memory device: an ellipse is contained, foci inside the bounding rectangle, c<ac < a. A hyperbola is unbounded, foci outside, c>ac > a. A second trap: check which semi-axis is larger. If the equation is x2/16+y2/49=1x^2/16 + y^2/49 = 1, the major axis is along yy.

What you now know

You can write the standard ellipse equation, identify major/minor axes, locate the foci via c=sqrta2b2c = \sqrt{a^2 - b^2}, compute eccentricity, and recognise a circle as the e=0e = 0 special case. The next section turns the sum-of-distances into a difference-of-distances and produces the hyperbola.

Quick check

Mark section complete →

References

  • Lang, S. (1971). Basic Mathematics. Springer. Chapter 12, §3.
  • Apostol, T. M. (1969). Calculus, Volume 2. Wiley. Chapter 13: conic sections and Kepler's laws.
  • Hartshorne, R. (2000). Geometry: Euclid and Beyond. Springer. Chapter 6: Apollonius's treatment.

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